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1). \(\frac{1}{{b - 4}}\)2). \(\frac{{b - 8}}{{b - 4}}\)3). \(\frac{{b - 4}}{{b - 7}}\)4). \(\frac{1}{{b - 8}}\) |
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Answer» $(\left( {1 - \frac{1}{{b - 4}}} \RIGHT)\left( {1 - \frac{1}{{b - 5}}} \right)\left( {1 - \frac{1}{{b - 6}}} \right)\left( {1 - \frac{1}{{b - 7}}} \right) = \frac{{b - 5}}{{b - 4}} \times \frac{{b - 6}}{{b - 5}} \times \frac{{b - 7}}{{b - 6}} \times \frac{{b - 8}}{{b - 7}} = \frac{{b - 8}}{{b - 4}})$ |
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