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1 litre solution containing 490 g of sulphuric acid is diluted to 10 litre with water. What is the normality of the resulting solution ?A. 0.5 NB. 1.0 NC. 5.0 ND. 10.0 N |
Answer» Correct Answer - B `N=(w_(B)xx1000)/(E_(B)xxV)=(490xx1000)/(49xx1000)=10` `N_(1)V_(1)=N_(2)V_(2)` `10xx1=N_(2)xx10` `N_(2)=1`] |
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