InterviewSolution
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InterviewSolution
| 1. |
`1 mg` gold undergoes decay with `2.7` days half-life period, amount left after `8.1` days isA. `0.91 mg`B. `0.25 mg`C. `0.5 mg`D. `0.125 mg` |
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Answer» Correct Answer - D (d) `N = N_0((1)/(2))^n rArr N = N_0 ((1)/(2))^(t//T_(1//2))` `rArr N = 1 xx ((1)/(2))^((8.1)/(2.7)) = ((1)/(2))^3 = (1)/(8)` `rArr N = (1)/(8) mg = 0.125 mg`. |
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