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1 mol of `N_(2)` and 2 mol of `H_(2)` are allowed to react in a 1 `dm^(3)` vessel. At equilibrium, `0.8` mol of `NH_(3)` is formed. The concentration of `H_(2)` in the vessel isA. 0.6 moleB. 0.8 moleC. 0.2 moleD. 0.4 mole |
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Answer» Correct Answer - B `{:(,N_(2),+,3H_(2),hArr , 2NH_(3)),("Initial ",1 "mol",,2"mol",,),("At eq.",1-0.4=0.6"mol",,2-3xx0.4=0.8"mol",,0.8"mol"):}` Formation of 0.8 mol of `NH_(3)` means of 0.4 mol `N_(2)` have reacted |
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