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There is 50% dimer formation of benzoic acid `(C_(6)H_(5)COOH)_(2)` in benzene solution. `2C_(6)H_(5)COOHhArr (C_(6)H_(5)COOH)_(2)`. Hence abnormal molecular weight of benzoic acid (theorectical value `=122g mol^(-1))` isA. 61 g `mol^(-1)`B. 244 g `mol^(-1)`C. 163 g `mol^(-1)`D. 81 g `mol^(-1)` |
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Answer» Correct Answer - C `M_(f)=122,M_(0)=?` `y=(1)/(2)` `x=50%=(1)/(2)` `x=(M_(f)-M_(0))/(M_(0)(y-1))` `(1)/(2)=(122-M_(0))/(M_(0)((1)/(2)-1))` `(1)/(2)=((M_(0)-122)^(2))/(M_(0))` `M_(0)=4(M_(0)-122)` `M_(0)=4M_(0)-122xx4` `3M_(0)=122xx4` `M_(0)=(122xx4)/(3)=162.67` `M_(0)~~163` |
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