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Which of the following equilibrium will shift left on increasing temperature. `(i) " " H_(2)O(g) hArr +1//2 O_(2)(g)` `(ii) " " CO_(2)(g) +C(s) hArr CO(g)` `(iii) " " C(s, "diamond") hArr C(s, "graphite")`A. Only (i)B. Both (i) and (ii)C. Only (iii)D. None |
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Answer» Correct Answer - C Out of diamond and graphite, at a given temperature graphite has lesser energy and the process `[Delta H^(@) ._(f) C ("graphite" )=0]`. `C(s,"diamond") hArr C(s, "graphite")` is an exothermic process. As such an increase in temperature shifts the equilibrium in the backward direction. |
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