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The equilibrium constant for the reaction `CaSO_(4).5H_(2)H_(2)O(s)hArr CaSO_(4).3H_(2)O(s)+2H_(2)O(g)` is equal toA. `([CaSO_(4).3H_(2)O][H_(2)O]^(2))/([CaSO_(4).5H_(2)O])`B. `([CaSO_(4).3H_(2)O])/([CaSO_(4).5H_(2)O])`C. `[H_(2)O]^(2)`D. `[H_(2)O].` |
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Answer» Correct Answer - C Concentration of solids is taken to be unity. Thus `[CaSO_(4).5H_(2)O(s)]` `[CaSO_(4).3H_(2)O(s)]=1` and `K=[H_(2)O]^(2)` |
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