1.

The equilibrium constant for the reaction `CaSO_(4).5H_(2)H_(2)O(s)hArr CaSO_(4).3H_(2)O(s)+2H_(2)O(g)` is equal toA. `([CaSO_(4).3H_(2)O][H_(2)O]^(2))/([CaSO_(4).5H_(2)O])`B. `([CaSO_(4).3H_(2)O])/([CaSO_(4).5H_(2)O])`C. `[H_(2)O]^(2)`D. `[H_(2)O].`

Answer» Correct Answer - C
Concentration of solids is taken to be unity.
Thus `[CaSO_(4).5H_(2)O(s)]`
`[CaSO_(4).3H_(2)O(s)]=1`
and `K=[H_(2)O]^(2)`


Discussion

No Comment Found

Related InterviewSolutions