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The vapour density of `N_(2)O_(4)` at a certain temperature is `30`. Calculate the percentage dissociation of `N_(2)O_(4)` this temperature.A. `53.3%`B. `106.6%`C. `26.7%`D. None |
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Answer» Correct Answer - A Mol. Wt. of `N_(2)O_(4)=92` Vapour density, `D=(92)/(2)=46` `N_(2)O_(4)(g) hArr 2NO_(2)(g)` Here `y=2` `d=30` `x=(D-d)/(d(y-1))=0.533=53.3%` |
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