1.

1 mole of an ideal gas expand isothermally and reversibly from a pressure of 10 atm to 1 atm at 300K. Calculate the height to which an object of 50 kg can be lifed by this expansion.

Answer»

Solution :`w_(("exp")) = -2.303nRT`
`LOG P_(i)//P_(f) = - 2.303 xx 1 MOL xx 8.314 JK^(-1) mol^(-1) xx 300K xx log 10//1 = 5.74 xx 10^(3)J`
Now, mgh `= 5.74 xx 10^(3) J or 50 kg xx 9.81 MS^(-2) xx h = 5.744 xx 10^(3)J`
`:. h = 11.7m`


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