1). x > y2). x < y3). x ≥ y4). x ≤ y

1.	1). x > y2). x < y3). x ≥ y4). x ≤ y
Answer» I. x² – 0.21x + 0.002 = 0 ⇒ x² – 0.01x – 0.2x + 0.002 = 0 ⇒ x(x – 0.01) – 0.2(x – 0.01) = 0 ⇒ (x – 0.01) (x – 0.2) = 0 Thus, x = 0.01 or 0.2 II. y² + 0.19y – 0.002 = 0 ⇒ y² + 0.2y – 0.01y – 0.002 = 0 ⇒ y(y + 0.2) – 0.01(y + 0.2) = 0 ⇒ (y + 0.2) (y – 0.01) = 0 Thus, y = – 0.2 or 0.01 So, when x = 0.01, for y = – 0.2, then x > y and when x = 0.01, for y = 0.01, then x = y And when x = 0.2, for y = – 0.2, then x > y and when x = 0.2, for y = 0.01, then x > y ∴ We can observe that x ≥ y

Answer»

I. x² – 0.21x + 0.002 = 0

⇒ x² – 0.01x – 0.2x + 0.002 = 0

⇒ x(x – 0.01) – 0.2(x – 0.01) = 0

⇒ (x – 0.01) (x – 0.2) = 0

Thus, x = 0.01 or 0.2

II. y² + 0.19y – 0.002 = 0

⇒ y² + 0.2y – 0.01y – 0.002 = 0

⇒ y(y + 0.2) – 0.01(y + 0.2) = 0

⇒ (y + 0.2) (y – 0.01) = 0

Thus, y = – 0.2 or 0.01

So, when x = 0.01, for y = – 0.2, then x > y and when x = 0.01, for y = 0.01, then x = y

And when x = 0.2, for y = – 0.2, then x > y and when x = 0.2, for y = 0.01, then x > y

∴ We can observe that x ≥ y

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