1.

10.0 g of CaCO_3on heating gave 4.4 g of CO_2 and 5.6g of CaO. The observation is in agreement with the

Answer»

law of constant COMPOSITION
law of multiple proportions
law of reciprocal proportion
law of conservation of mass

Solution :`CaO_3 to CAO + CO_2`
mass of REACTANT = 10.0 g
mass of products = mass of CaO + mass of `CO_2`
= 5.6 +4.4 = 10.0 g
As mass of reactant = mass of products. The OBSERVATION is in agreement with law of conservation of mass.


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