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`10^14` fissions per second are taking place in a nuclear reactor having efficiency `40%`. The energy released per fission is 250MeV. The power output of the reactor isA. 2000WB. 4000WC. 1600WD. 3200W |
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Answer» Correct Answer - C Power output =0.4 x power input =0.4x 250 `xx10^(6) xx1.6xx10^(-19)xx10^(14)=1600 W`. |
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