10 cm high object is placed at a distance of 25 cm from a converging lens of focal length of 10 cm . Determine the position, size and type of the image.

10 cm high object is placed at a distance of 25 cm from a converging l

1.	10 cm high object is placed at a distance of 25 cm from a converging lens of focal length of 10 cm . Determine the position, size and type of the image.
Answer» Solution :Data : Convergin lens , `f=10 cm` `u=-25 cm, h_(1)=10cm, v= ? "h"_(2)=? ` `1/f =1/v -1/u therefore 1/v=1/f +1/u` `therefore 1/v =(1)/(10cm)+(1)/(-25cm)=(1)/(10cm) -(1)/(25 cm)` `=(5-2)/(50 cm)=(3)/(50 cm)` `therefore ` Image distance ,` v=(50)/(3) cm` `DIV 16.67 cmdiv 16.7 cm` (ii) `(h_(2))/(h_(1))=(v)/(u) therefore h_(2)=(v)/(u) h_(1)` `therefore h_(2) ((50//3)cm)/(-25)xx10 cm=(50xx10)/(25xx3)cm ` `=-(20)/(3)` cm div -6.666 cm` `div -6.6 cm` The height of the image =-6.6 cm (inverted image : MINUS sign). (iii) The image is REAL, inverted and smaller than the object.