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`10 g` of glucose (molar mass 180) and `20 g` of sucrose (molar mass 342) are dissolved in `100 g` of water. What will be the vapour pressure of the resultant solution if the vapour pressure of water is `30 mm Hg`? |
Answer» Mass of glucose = 10g No. of moles of glucose = 0.0556 Mass of sucrose = 20g No. of moles of sucrose = 0.0585 Mass of water = 100g No. of moles of water = 5.556 Total number of moles `= 5.556+0.0585+0.0556` `=5.67` Mole fraction of water `= (5.556)/(5.67)` Vapour pressure of solution = Mole fraction of water `xx p_(0)` `=(5.556)/(5.67) xx 35 = 34.3` mm Hg. |
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