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`10 gm` of radioactive material of half-life `15` year is kept in store for `20` years, The disintegrated material is.A. `12.5 g`B. `10.5 g`C. `6.03 g`D. `4.03 g` |
Answer» Correct Answer - C ( c) Remaining material `N = (N)/(2^(t//T))` `rArr N = (10)/((2)^(20//15)) = (10)/(2.15) = 3.96 gm` So decayed material `= 10 - 3.9 = 9.04 gm`. |
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