1.

10 men can complete a piece of work in 34 days, 16 women can complete the same piece of work in 56 days. 5 men and 18 women work together for 20 days. If only women were to complete the remaining piece of work in 4 days along with a boy who does 10 units of work per day, how many women would be required?1). 532). 683). 584). 54

Answer»

The amount of work done by 10 MEN in 34 DAYS = amount of work done by 16 women in 56 days

⇒ 10 ? men ? 34 = 16 ? women ? 56

⇒ Men/women = 224/85

⇒ Amount of work done by a man in 1 day = 224

⇒ Amount of work done by a women in 1 day = 85

⇒ Total work = 10 ? men ? 34 = 10 ? 224 ? 34 = 76160

⇒ Work done by 6 men and 18 women in 20 days = (5 ? men + 18 ? women) ? 20

⇒ (5? 224 + 18 ? 85) ? 20 = 53000

⇒ Work LEFT = 76160 – 53000 = 23160

Work done by Boy for 4 days = 4 × 10 = 40 Units

⇒ Remaining work = 23160 – 40 = 23120

∴ Number of women required to finish the remaining work = $(\frac{{23120}}{{4\; \times \;85}}\; = \;68)$ women


Discussion

No Comment Found

Related InterviewSolutions