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10 men can complete a piece of work in 34 days, 16 women can complete the same piece of work in 56 days. 5 men and 18 women work together for 20 days. If only women were to complete the remaining piece of work in 4 days along with a boy who does 10 units of work per day, how many women would be required?1). 532). 683). 584). 54 |
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Answer» The amount of work done by 10 MEN in 34 DAYS = amount of work done by 16 women in 56 days ⇒ 10 ? men ? 34 = 16 ? women ? 56 ⇒ Men/women = 224/85 ⇒ Amount of work done by a man in 1 day = 224 ⇒ Amount of work done by a women in 1 day = 85 ⇒ Total work = 10 ? men ? 34 = 10 ? 224 ? 34 = 76160 ⇒ Work done by 6 men and 18 women in 20 days = (5 ? men + 18 ? women) ? 20 ⇒ (5? 224 + 18 ? 85) ? 20 = 53000 ⇒ Work LEFT = 76160 – 53000 = 23160 Work done by Boy for 4 days = 4 × 10 = 40 Units ⇒ Remaining work = 23160 – 40 = 23120 ∴ Number of women required to finish the remaining work = $(\frac{{23120}}{{4\; \times \;85}}\; = \;68)$ women |
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