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10 mL of a solution of NaOH is found to be completely neutralised by 8 mL of a given solution of HCl. If we take 20 mL of the same solution of NaOH, the amount HCl solution (the same solution as before) required to neutralise it will be |
Answer» Solution :The amount of HCl required will increase proportionately because the concentrations of both the NAOH and HCl solutions remain the same. The amount of HCl required will be ` 8 xx (20)/(10) = 16 mL` THUS option (d) is correct. |
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