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100 cc of `0.6 N H_(2)SO_(4)` and 200 cc of `0.3 N HCI` were mixed together. The normality of the solution will beA. 0.2NB. 0.4NC. 0.8ND. 0.6N |
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Answer» Correct Answer - B Total volume of solution `= 100+200=300` cc For `H_(2)SO_(4)` `N_(1)V_(1)=N_(2)V_(2)` `0.6N xx100=N_(2)xx300` `N_(2)=(60N)/(300)=(N)/(5)` For HCl `N_(1)V_(1)=N_(2)V_(2)` `0.3N xx200=N_(2)xx300` `N_(2)=(N)/(5)` Total normality `= N(H_(2)SO_(4))+N(HCl)` `=(N)/(5)+(N)/(5)=(2N)/(5)=0.4N` |
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