1.

100 cc of `0.6 N H_(2)SO_(4)` and 200 cc of `0.3 N HCI` were mixed together. The normality of the solution will beA. 0.2NB. 0.4NC. 0.8ND. 0.6N

Answer» Correct Answer - B
Total volume of solution `= 100+200=300` cc
For `H_(2)SO_(4)`
`N_(1)V_(1)=N_(2)V_(2)`
`0.6N xx100=N_(2)xx300`
`N_(2)=(60N)/(300)=(N)/(5)`
For HCl
`N_(1)V_(1)=N_(2)V_(2)`
`0.3N xx200=N_(2)xx300`
`N_(2)=(N)/(5)`
Total normality `= N(H_(2)SO_(4))+N(HCl)`
`=(N)/(5)+(N)/(5)=(2N)/(5)=0.4N`


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