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1000 kW of power is supplied to a motor. 90% of this is transmitted to a machine operating at 80% efficiency. The machine lifts an object of 10-tons with a velocity _____ m/s. (Assume g = 10m/s^2)(a) 2(b) 4(c) 6(d) 8The question was asked in my homework.This question is from Power in chapter Work, Energy and Power of Physics – Class 11

Answer»

Correct ANSWER is (c) 6

Easiest explanation: Power transmitted to machine = (90/100) x (1000) kW

 = 900 kW

Power USED to LIFT OBJECT = (80/100) x 900 KW

 = 720 kW

7,20,000 = F x v

 = (1/2 x m x v^2) x v

 = 10,000/2 x v^3

v^3 = 216

v = 6 m/s.



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