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12 V, 9 V and 12 V bulbs are connected in series. What is the potential difference of their combination ? |
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Answer» Solution :1. `V_(C)=V_(1)+V_(2)+V_(3)` 2. `V_(c)=12V+9V+12V` 3. `V_(c)=33V` Potential Difference of their COMBINATION is 33 V. |
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