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12 V battery is connected in a circuit and to this 4W, 12W, resistors are connected in circuit from this information and the current in the circuit. |
Answer» Solution : The RESULTANT RESISTANCE of 4W. 12W connected in parallel is `(1)/(R)=(1)/(R_(1))+(1)/(R_(2))` `(1)/(R)=(1)/(4)+(1)/(12)rArr(1)/(R)=(3+1)/(12)` `therefore(1)/(R)=(4)/(12)rArrR=(12)/(4)` `thereforeR=3Omega` The total resistance in the CIRCUIT is `R=R_(1)+R_(2)=3+3=6` `thereforeR=6Omega` The current in the circuit `I=(V)/(R)rArrI(12)/(6).` `thereforeI=2A` |
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