14.3 g of Na_(2)CO_(3) xH_(2)O is dissolved in water and the volume is made up to 200 mL. 20 mL of this solution required 40 mL of (N)/(4) HNO_(3) for complete neutralisation. Calculate x

14.3 g of Na_(2)CO_(3) xH_(2)O is dissolved in water and the volume is

1.	14.3 g of Na_(2)CO_(3) xH_(2)O is dissolved in water and the volume is made up to 200 mL. 20 mL of this solution required 40 mL of (N)/(4) HNO_(3) for complete neutralisation. Calculate x
Answer» SOLUTION :`V_(1) N_(1) = N_(2) V_(2)` `20 (N_(1)) = 40 XX 0.25` `N_(1) = 0.5 N` Normality of `Na_(2)CO_(3) XH_(2)O` solution is 0.5 `0.5 = (14.3)/("Eq.WT") xx (1000)/(200)` Eq. Wt `= (14.3 xx 5)/(0.5)` Eq. Wt = 143 But equivalent weigth `Na_(2) CO_(3) XH_(2)O` is `(106 + x(18))/(2) = 143` `:. x = (286 - 106)/(18)` `x= 10` `:. Na_(2) CO_(3) . 10H_(2)O`