1.

`(15)/(16)th` of a radioactive sample decays in 40 days. Half-life of the sample isA. 100 daysB. 10 daysC. 1 dayD. `log_(e) 2` days

Answer» Correct Answer - B
Quantity of radioactive element decayed = `(15)/(16)`
Quantity left `= 1 - (15)/(16) = (1)/(16)`
`(1)/(16) = 1 xx ((1)/(2))^(n) or ((1)/(2))^(4) = ((1)/(2))^(n)`
one half-life `= (40)/(4) = 10` days.


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