√1850 × √1160 ÷ √290 = ? × 7 - 121). 152). 143). 174). 686

1.	√1850 × √1160 ÷ √290 = ? × 7 - 121). 152). 143). 174). 686
Answer» Follow BODMAS rule to solve this QUESTION, as per the order given below, Step-1 - Parts of an equation enclosed in 'Brackets' must be solved FIRST, and in the bracket, Step-2 - Any mathematical 'Of' or 'Exponent' must be solved next, Step-3 - Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated, Step-4 - Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated. Given expression is, √1850 × √1160 ÷ √290 = ? × 7 - 12 Taking Approximate values, √1850 ≈ √1849, √1160 ≈ √1156, √290 ≈ √289 ⇒ 43 × 34 ÷ 17 = ? × 7 - 12 ⇒ 7 × ? = 86 + 12 = 98 ∴ ? = 14

Answer»

Follow BODMAS rule to solve this QUESTION, as per the order given below,

Step-1 - Parts of an equation enclosed in 'Brackets' must be solved FIRST, and in the bracket,

Step-2 - Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3 - Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4 - Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Given expression is,

√1850 × √1160 ÷ √290 = ? × 7 - 12

Taking Approximate values,

√1850 ≈ √1849, √1160 ≈ √1156, √290 ≈ √289

⇒ 43 × 34 ÷ 17 = ? × 7 - 12

⇒ 7 × ? = 86 + 12 = 98

∴ ? = 14

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