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`18g` glucose `(C_(6)H_(12)O_(6))` is added to `178.2g` water. The vapour pressure of water (in torr) for this aqueous solution is:A. 7.6B. `76.0`C. 752.4D. `759.0` |
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Answer» Correct Answer - C `(Deltap)/(p_(0))=x_(B)` `Deltap=x_(B)xxp_(0)` `=(n_("glucose"))/(n_("water")+n_("glucose"))xxp_(0)` `Deltap=(0.1)/(9.9+0.1)xx760` `p_(0)-p=7.6` `p=p_(0)-7.6` `=760-7.6` `=752.4` torr] |
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