1.

`18g` glucose `(C_(6)H_(12)O_(6))` is added to `178.2g` water. The vapour pressure of water (in torr) for this aqueous solution is:A. 7.6B. `76.0`C. 752.4D. `759.0`

Answer» Correct Answer - C
`(Deltap)/(p_(0))=x_(B)`
`Deltap=x_(B)xxp_(0)`
`=(n_("glucose"))/(n_("water")+n_("glucose"))xxp_(0)`
`Deltap=(0.1)/(9.9+0.1)xx760`
`p_(0)-p=7.6`
`p=p_(0)-7.6`
`=760-7.6`
`=752.4` torr]


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