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`18g` of glucose `(C_(6)H_(12)O_(6))` is added to `178.2g` of water. The vapour pressure of water for this aqueous solution at `100^(@)C` is-A. `7.60` TorrB. `76.00` TorrC. `752.40` TorrD. `759.00` Torr |
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Answer» Correct Answer - C `PA = P_(A)^(@) x_(A) = 760 xx (178.2//18)/((178.2)/(18)+(18)/(180))` `= 760 xx (9.9)/(10) = 752.4` torr |
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