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`2.5 g` of a substance is present in `200 mL` of solution showing the osmotic pressure of `60 cm Hg` at `15^(@)C`. Calculate the molecular weight of substance.What will be the osmotic pressure if temperature is raised to `25^(@)C`? |
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Answer» Given that, `W_(2)=2.5 g` ,`V=200/1000 L` `pi=60/70` atm, `T=288 K` `:. piV=W_(2)/(Mw_2)RT` `60/70 xx 200/1000 = 2.5/(Mw_2)xx 0.0821 xx288 rArr Mw_(2)=374.38` Also, `pi_(1)/pi_(2)=T_(1)/T_(2)` `60/pi_(2)=288/298 rArr pi_(2) = 62.08 cm` |
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