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20 mL of a solution os sulphuric acid neuitralise 21.2 mL of 30% soution of sodium carbonete. How much water should be added to 100 mL of this solutio to bring down its down its strength to decinoral? |
Answer» Calculation of normality of suplhric acid solution strength of `Na_(2)CO_(3)` solution=`130g//100mL =300gL^(-1)` ` "Normality of" Na_(2)CO_(3) "solution"=("Strength")/("Equivalent mass")= (300gL^(-1))/(53g equiv^(-1))` `=5.66"equiv." L^(-1)=5.66 N`. `N_(1)xxV_(1)=N_(2)xxV_(2)or N_(1)=(N_(2)xxV_(2))/V_(1)` `(H_(2)SO_(4))=(Na_(2)CO_(3))` `N_(1)=((5.66N)xx(21.2mL))/((20.0mL))=6.0N`. Calculation of volume of water to be added Normality of `H_(2)SO_(4)` solution=6.0N volume of `H_(2)SO_(4)` solution=100mL Normality of diluted `H_(2)SO_(4)` solution=0.1N Volume of diluted `H_(2)SO_(4)` solution may be calculated as: `"underset"(("diluted" H_(2)SO_(4)))(N_(1)xxV_(1))=underset(("Concentreated"H_(2)SO_(4)))(N_(2) xx V_(2))` `V_(1)=(N_(2)xxV_(2))/N_(1)=((6.0N)xx(100mL))/((0.1N))=6000mL` Volume of water to be added =(6000-100)=5900mL |
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