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200.0 mL of calcium chloride solution sotains `3.10xx10^(22)CI^(-)` inoc. Calculate the molarity of the solution. Assume that calcium cholride is complately ionised. |
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Answer» Correct Answer - 0.125 M Setp I. Calculation of mass of `CaCI_(2)` present in solution. lonisation of `CaCI_(2)` and no. of different species in the soluion may be represented as follows : `CaCI(s)overset((aq))toca^(2+)(aq)+2CI^(-)(aq)` `(1.505xx10^(22)"molecules")(1.505xx10^(22))(3.01xx10^(22))` `6.022xx10^(22)"molecules of"CaCI_(2) " correspond to mass"=(1.505xx10^(22))/(6.022xx10^(23))xx(111g)=2.774 g` Step II. Calculation of molarity of solution. `"Molarity of soluion (M)"=("Mass of "CaCI_(2)//"Molar mass")/("Volume of solution in Litress")` `((2.774g)//(111" g mol"^(-1)))/(200//1000L)=0.125" mol L"^(-1)=0.125 M` |
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