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`200cm^(3)` of an aqueous solution contains 1.26g of a polymer. The osmotic pressure of such solution at 300K is found to be `2.57 xx 10^(-3)` bar. Calculate the molar mass of the polymer. |
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Answer» `piV=(w_(B))/(m_(B))RT` `m_(B)=(w_(B))/(V)xx(RT)/(pi)` `=(1.26)/(0.2)=(0.083xx300)/(2.57xx10^(-3))=61038"g mol"^(-1)`. |
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