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214.2 gram of sugar syrup contains 34.2 gram of sugar. Caluculate (i) molality of the solution and (ii) mole fraction of the sugar in the syrup- |
Answer» (i) Mass of sugar = 34.2g No. of moles of sugar `= (34.2)/("Mol.mass")=(34.2)/(342)=0.1` Mass of water `=(214.2-34.2)` `= 180g = (180)/(1000)kg` No. of moles of water `= (180)/(18)=10` Molality `= ("No. of moles of sugar")/("Mass of water in kg")=(0.1)/(180)xx1000` `=0.555m` (ii) Total number of moles `=10.0+0.1=10.1` Mole fraction of sugar `= ("No.of moles of sugar")/("Total number of moles")` `=(0.1)/(10.1)=0.0099`. |
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