`29.2% (w//w) HCl` stock, solution has a density of `1.25 g mL^(-1)`. The molecular weight of `HCl` is `36.5 g mol^(-1)`. The volume `(mL)` of stock solution required to prepare a `200 mL` solution of `0.4 M HCl` is :

`29.2% (w//w) HCl` stock, solution has a density of `1.25 g mL^(-1)`.

1.	`29.2% (w//w) HCl` stock, solution has a density of `1.25 g mL^(-1)`. The molecular weight of `HCl` is `36.5 g mol^(-1)`. The volume `(mL)` of stock solution required to prepare a `200 mL` solution of `0.4 M HCl` is :
Answer» Correct Answer - 8 Molarity `(M_(1))`of stock concentrated solution can be calculated using following relation : `M_(1)(x xx d xx10)/(m_(B))` `=(29.2xx1.25xx10)/(36.5)=10` `M_(1)V_(1)` (Concentrated) `= M_(2)V_(2)` (Diluted) `10xxV_(1)=0.4xx200` `V_(1)=8mL`]

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`29.2% (w//w) HCl` stock, solution has a density of `1.25 g mL^(-1)`. The molecular weight of `HCl` is `36.5 g mol^(-1)`. The volume `(mL)` of stock solution required to prepare a `200 mL` solution of `0.4 M HCl` is :

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