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`2N HCI` solution will have the same molar concentration as aA. `4.0 N H_(2)SO_(4)`B. `0.5 NH_(2)SO_(4)`C. `1N H_(2)SO_(4)`D. `2N H_(2)SO_(4)` |
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Answer» Correct Answer - A `2N HCl=2g eq L^(-1)=2 mol L^(-1)` [Eqn. mass = Mol mass] `4N H_(2)SO_(4)=4g eq L^(-1) = 4xx49 g L^(-1)` `=4xx(49)/(98)=2 mol L^(-1)` (Eq. mass of `H_(2)SO_(4)=49` , Mol mass = 98) |
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