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`2sin^2(pi/6 )+c o s e c^2((7pi)/6)cos^2(pi/3)=3/2`

Answer» `L.H.S.=2sin^2(pi/6)+cosec^2((7pi)/6)cos^2(pi/3)``=2sin^2(pi/6)+cosec^2(pi+pi/6)cos^2(pi/3)``=2sin^2(pi/6)+cosec^2(-pi/6)cos^2(pi/3)``=2(1/2)^2 +(-2) ^2**1/4 = 1/2+1 = 3/2=R.H.S.`


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