3.4 g H2O2 is dissolved in 448 mL solution. Thesolution will be labell

1.	3.4 g H2O2 is dissolved in 448 mL solution. Thesolution will be labelled as (V = Vol. strength):-A) 0.224VB) 5VC) 2.5VD) 20V
Answer» Strength of H₂O₂ = \(\frac{Weight\,of\,H_2O_2}{Volume\,of\,solution(L)}\) = \(\frac{3.4g\times1000}{448L}\) = 7.6 g/L \(\underset{(2\times34g)}{2H_2O_2}\longrightarrow2H_2O+\underset{(22.4L)\,at\,NTP}{O_2}\) 68 g of H₂O₂ produces 22.4 litres at oxygen gas at NTP. Therefore, 7.6g of H₂O₂ will produce = 22.4/68 x 7.6 = 2.5 litre at oxygen. Thus, volume strength of given H₂O₂ solution is 2.5 Hence, option(c) is Right answer.

3.4 g H2O2 is dissolved in 448 mL solution. Thesolution will be labelled as (V = Vol. strength):-A) 0.224VB) 5VC) 2.5VD) 20V

Answer»

Strength of H₂O₂ = \(\frac{Weight\,of\,H_2O_2}{Volume\,of\,solution(L)}\)

= \(\frac{3.4g\times1000}{448L}\)

= 7.6 g/L
\(\underset{(2\times34g)}{2H_2O_2}\longrightarrow2H_2O+\underset{(22.4L)\,at\,NTP}{O_2}\)

68 g of H₂O₂ produces 22.4 litres at oxygen gas at NTP.

Therefore,

7.6g of H₂O₂ will produce

= 22.4/68 x 7.6

= 2.5 litre at oxygen.

Thus, volume strength of given H₂O₂ solution is 2.5

Hence, option(c) is Right answer.

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3.4 g H2O2 is dissolved in 448 mL solution. Thesolution will be labelled as (V = Vol. strength):-A) 0.224VB) 5VC) 2.5VD) 20V

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