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3.65grams of HCI dissolved in 16.2g of water. The mole fraction of HCI in the resulting solution isA. 0.4B. 0.3C. 0.2D. 0.1 |
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Answer» Correct Answer - D `n(HCI) = (3.65)/(36.5) = 0.1mol` `n(H_(2)O) = (16.2)/(18) = 0.9` mol `X (HCI) = (n(HCI))/(n(HCI)+n(H_(2)O))` `= (0.1)/(0.1+0.9) = 0.1` |
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