1.

\((3+\frac{5}{-7})=\,?\)A. \(\frac{-16}{7}\)B. \(\frac{16}{7}\)C. \(\frac{-26}{7}\)D. \(\frac{-8}{7}\)

Answer»

\(3=\frac{3}{1}\)

\(\frac{5}{-7}=\frac{5\times-1}{-7\times-1}=\frac{-5}{7}\)

\(\Rightarrow\) \(3+\frac{5}{-7}=\frac{3}{1}+\frac{-5}{7}\)

\(=\frac{3\times7+(-5)\times1}{7}\)

\(=\frac{21-5}{7}\)

\(=\frac{16}{7}\)



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