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\((3+\frac{5}{-7})=\,?\)A. \(\frac{-16}{7}\)B. \(\frac{16}{7}\)C. \(\frac{-26}{7}\)D. \(\frac{-8}{7}\) |
Answer» \(3=\frac{3}{1}\) \(\frac{5}{-7}=\frac{5\times-1}{-7\times-1}=\frac{-5}{7}\) \(\Rightarrow\) \(3+\frac{5}{-7}=\frac{3}{1}+\frac{-5}{7}\) \(=\frac{3\times7+(-5)\times1}{7}\) \(=\frac{21-5}{7}\) \(=\frac{16}{7}\) |
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