1.

3 resistors R_1,R_2 and R_3 are connected in series to a battery. Draw the circuit diagram showing the arrangement. Derive an expression for the equivalent resistance of the combination. (b) Resistors are given as R_1=10 Omega, R_2=20 Omega and R_3=30 Omega. Calculate the effective resistance when they are connected in series . Also calculate the current flowing when the combination is connected to a 6V battery.

Answer»

Solution :(B) Here `R_1=10 Omega, R_2=20 Omega and R_3=30 Omega`
`therefore` Effective RESISTANCE in series `R=R_1+R_2+R_3=10+20+30=60 Omega`
As voltage of battery V=6V
`therefore` Current flowing in series COMBINATION of resistors
`I=V/R=(6V)/(60 Omega)=0.1A`


Discussion

No Comment Found