InterviewSolution
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InterviewSolution
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`(30)^(3) + (20)^(3) - (50)^(3)` का मान ज्ञात कीजिए । |
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Answer» यहाँ `x^(3) + y^(3) + z^(3) = 3xyz` यदि `x + y + z = 0` व `x^(3) + y^(3) + z^(3) - 3xyz = (x + y + z)(x^(2) + y^(2) + z^(2) - xy - yz - zx)` यदि `x + y + z ne 0` दिया है `(30)^(3) + (20)^(3) - (50)^(30)` या `(30)^(3) + (20)^(3) + (-50)^(3)` `therefore` माना `x = 30, y = 20, z = - 50` अब, `x + y + z = 30 + 20 + (-50) = 0` क्योकि `x + y + z = 0" "therefore" "x^(3)+y^(3)+z^(3)=3xyz` `(30)^(3)+(20)^(3)-(50)^(3)=3(30) (20) (-50) = - 90000` |
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