1.

300 mL solution at 27 °C contains 0.2 mol of a nonvolatile solute. Calculate osmotic pressure of the solution.

Answer»

Given : 

V = 300 ml = 0.3 dm3

T = 273 + 27 = 300 K 

π = 0.2 mol, 

π = ?

π = \(\frac{nRT}{V}\)

\(\frac{0.2\times0.08206\times 300}{0.3}\)

= 16.41 atm

∴ Osmotic pressure = π = 16.41 atm.



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