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300 mL solution at 27 °C contains 0.2 mol of a nonvolatile solute. Calculate osmotic pressure of the solution. |
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Answer» Given : V = 300 ml = 0.3 dm3 ; T = 273 + 27 = 300 K π = 0.2 mol, π = ? π = \(\frac{nRT}{V}\) = \(\frac{0.2\times0.08206\times 300}{0.3}\) = 16.41 atm ∴ Osmotic pressure = π = 16.41 atm. |
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