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33 The position vector of a particle moving in x-y plane is given by r (t 4) i (t 4) j. Find (a) Equation of trajectory of the particle Albo in a (b) Time when it crosses x-axis and y-axis |
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Answer» To find the trajectory,`vecr =xhati+ yhatj=(t^2-4)hati+ (t-4)hatj` So, `x=t^2 -4` and `y=t-4` On solving,`x=(y+4)^2-4` `y^2-8y-x+12=0` Time when it crosses x-axis,`t-4=0``t=4sec` Time when it crosses y-axis,`t^2-4=0``t=2sec` |
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