1.

(3a + 1 9a + 2 27a)÷ (3a - 1 9a 27a + 1) = ?1). 12). 93). 274). 3

Answer»

Solve the given QUESTION, using following laws of indices,

Laws of Indices,

1-: am × an = a{m + n}

2-: am ÷ an = a{m - n}

3-: [(am)n] = amn

4-: (a)1/m = $(\sqrt[m]{a})$

5-: (a)-m = 1/am

6-: (a)(m/n) = $(\sqrt[n]{{{a^m}}})$

7-: a0 = 1

$(\begin{array}{L} \Rightarrow \frac{{{3^{a + 1}}\;{9^{a + 2}}\;{{27}^a}}}{{{3^{a - 1}}\;{9^a}\;{{27}^{a + 1}}}} = {\rm{\;}}?\\ \Rightarrow ? = \frac{{{3^{a + 1}}\;{3^{2\left( {a + 2} \right)}}\;{3^{3a}}}}{{{3^{a - 1}}\;{3^{2a}}\;{3^{3\left( {a + 1} \right)}}}}\\ \Rightarrow ? = \frac{{\;{3^{6a + 5}}}}{{{3^{6a + 2}}}} \end{array})$

⇒ ? = 33

⇒ ? = 27


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