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`4` grams of radioactive substance `A` left `1//2 gm` after some ture. `1` gran of another radioactive substance `B` left `1//4 gm` in the same period, If half life of `B` is `2` hours, the half life of `A` is ( in hours)A. `3//4`B. `4//3`C. `1//4`D. `1//2` |
Answer» Correct Answer - B `W=(W_(0))/(2^(n))`, no of half lives `n=(t)/(t_(1//2))` |
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