(4 × 6 – 18 ÷ 3) × [192 ÷ {(5 + 3) × 4} – 2]1). 82). 183). 24

1.	(4 × 6 – 18 ÷ 3) × [192 ÷ {(5 + 3) × 4} – 2]1). 82). 183). 244). 72
Answer» USING the BODMAS rule, B – Bracket in order (), {}, [] O – of D – Division M – Multiplication A – Addition S - Subtraction (4 × 6 – 18 ÷ 3) × [192 ÷ {(5 + 3) × 4} – 2] (24 – 6) × [192 ÷ {8 × 4} – 2] ⇒ 18 × [192 ÷ 32 – 2] ⇒ 18 × [6 – 2] ⇒ 18 × 4 ∴ (4 × 6 – 18 ÷ 3) × [192 ÷ {(5 + 3) × 4} – 2] = 72

(4 × 6 – 18 ÷ 3) × [192 ÷ {(5 + 3) × 4} – 2]1). 82). 183). 244). 72

Answer»

B – Bracket in order (), {}, []

O – of

D – Division

M – Multiplication

A – Addition

S - Subtraction

(4 × 6 – 18 ÷ 3) × [192 ÷ {(5 + 3) × 4} – 2]

(24 – 6) × [192 ÷ {8 × 4} – 2]

⇒ 18 × [192 ÷ 32 – 2]

⇒ 18 × [6 – 2]

⇒ 18 × 4

∴ (4 × 6 – 18 ÷ 3) × [192 ÷ {(5 + 3) × 4} – 2] = 72