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5.6 litre of oxygen at S.T.P |
Answer» Solution :Given volume of `O_(2)` at `"NUMBER of MOLES"=("S.T.P.")/("Molar volume at S.T.P")` `=46//23` `"Number of moles of OXYGEN"=(5.6)/(22.4)="0.25 mole of oxygen"` |
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