1.

5.6 litre of oxygen at S.T.P

Answer»

Solution :Given volume of `O_(2)` at
`"NUMBER of MOLES"=("S.T.P.")/("Molar volume at S.T.P")`
`=46//23`
`"Number of moles of OXYGEN"=(5.6)/(22.4)="0.25 mole of oxygen"`


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