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5.85 g of NaCI is dissoloved in water and the solution is made upto 0.5 litre. The molarity of solution is:A. 1 MB. 2 MC. 0.1 M `BaCI_(2)`D. 0.2 M |
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Answer» Correct Answer - d `"Molarity of solution (M)"=("Mass of NaCI/Molar Mass")/("Volume of solutin in liters")` ` =((5.85g)//(58.5g mol^(-1)))/((0.5 L))` `=((0.1 mol))/((0.5 L))=0.2 mol L^(-1)=0.2 M` |
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