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1. |
5 mL each of concentrated HCl and concentrated HNO3 are taken in test tubes labelled as A and B while a mixture of concentrated HCI (15 mL) and concentrated HNO_3(5 mL) is taken in test tube labelled as C. A small piece of metal is placed in each test tube. No change is observed in test tubes A and B, but metal got dissolved in test tube C. What would be the metal ? |
Answer» Solution :Metal WOULD be silver, GOLD or PLATINUM | |