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50 g of saturated solution of NaCl at 30^@ C is evaporated to dryness and 13.2 g of dry NaCl was obtained. Find the solubility of NaCl at 30^@ C in water. |
Answer» SOLUTION :Massof water in solution `= 50-13.2=36.8 g` Solubility of NACL `=( "MASS of NaCl ")/("Mass of water")xx 100` `= ( 13.2 )/( 36.8 )xx 100 =36 g ` Solubilityof NaCl=36 g ( APPX.) |
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