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5cm high object is placed at a distance of 25 cm from a converging lens of focal length of 10 cm. Determine the position, size and type of the image. |
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Answer» Solution :Given: `h_(1) = 5 CM` U = 25 cm f = 10 cm (Converging LENS) To find: Position, size and type of image Solution :`1/V - 1/u = 1/f ` `1/v - 1/-25 =1/10` `1/v + 1/25 = 1/10` = `1/10 - 1/25` `(1/Y)/V = (5-2)/(50)` `1/v = 3/50` v = `50/3 ` `therefore`V = 16.7 cm `v/u = (h_(2))/(h_(1))` `(50/3)/25= (h_(2))/5` `50/3 xx 5/25 = h_2` |
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