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5mL of `N HCI, 20 mL` of `N//2 H_(2)SO_(4)` and 30 mL of `N//3 HNO_(3)` are mixed together and volume made to one litre. The normality of the resulting solution isA. `(N)/(5)`B. `(N)/(10)`C. `(N)/(20)`D. `(N)/(40)` |
Answer» Correct Answer - D For `HCI`, `N_(1)V_(1) = N_(2)V_(2)` `N xx 5 = N_(2) xx 1000` `N_(2) = 5 xx 10^(-3) N =0.5 xx 10^(-2)N` For `H_(2)SO_(4)`, `N_(1)V_(1) = N_(2)V_(2)` `(N)/(2) xx 20 = N_(2) xx 1000` `N_(2) = 10^(-2)N` For `HNO_(3)`, `N_(1)V_(1) = N_(2)V_(2)` `(N)/(3) xx 30 = N_(2) xx 1000` `N_(2) = 10^(-2) N` Total normality `= N(HCI) + N(H_(2)SO_(4)) + N (HNO_(3))` `= (0.5 xx 10^(-2) +106(-2) +10^(-2)) N` `= 2.5 xx 10^(-2)N` `(25)/(1000) N = (N)/(40)` |
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